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4.9x^2+3x-350=0
a = 4.9; b = 3; c = -350;
Δ = b2-4ac
Δ = 32-4·4.9·(-350)
Δ = 6869
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6869}=\sqrt{1*6869}=\sqrt{1}*\sqrt{6869}=1\sqrt{6869}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-1\sqrt{6869}}{2*4.9}=\frac{-3-1\sqrt{6869}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+1\sqrt{6869}}{2*4.9}=\frac{-3+1\sqrt{6869}}{9.8} $
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